Tail inflation
A rare common-cause branch can dominate the probability of many simultaneous failures.
Reliability
Run a seeded component-failure Monte Carlo model with an explicit common-cause branch.
MONTE CARLO SCENARIO
For reliability teams testing redundancy thresholds when independent component risk is not the whole story.
CURRENT DECISION RECORD
Every row is regenerated from the active inputs and carried into Copy, TXT, and the page-specific PDF payload.

| Failed components | Simulated trials | Trial share (%) |
|---|
CURRENT CALCULATION PROCESS
F = N with probability q; otherwise F ~ Binomial(N,p)
Waiting for valid inputs.
HOW TO USE
FOUNDATIONS
DEEP ANALYSIS
A rare common-cause branch can dominate the probability of many simultaneous failures.
The mixture mean N[q+(1-q)p] provides an independent deterministic check.
Set it from the consequence or redundancy rule before looking at simulated results.
CASES
Low p and q=0 produces a familiar binomial-like histogram concentrated near zero.
Even a small q places mass at all components failed and can sharply raise the threshold probability.
TERMS
EVIDENCE RECORD
Archive component count, independent probability, common-cause probability, threshold, iterations, seed, model revision, and alternate-seed results. Preserve the engineering basis for p and q separately so reviewers can reproduce the mixture and challenge the shared-shock assumption.
MODEL LIMITS
SOURCES
FAQ
It initializes a deterministic xorshift32 stream so the same inputs reproduce the same table.
The common-cause branch changes the tail and simulation makes that mixed outcome tangible.
The model applies q first; independent failures run only when the common-cause event does not occur.
Enough depends on the tail probability and precision needed; compare seeds and report Monte Carlo uncertainty.
Not here; this page uses an explicit all-component shock branch.
No. Five percent of simulated trials can be at or above it, subject to ties.
IMPORTANT SIMULATION NOTE
The seeded result illustrates the entered mixture. It does not establish the true shared-shock probability, independence of the remaining component failures, or safety of the threshold.