Fatigue usually governs rotating bending
A surface point on a rotating shaft cycles between tension and compression. Endurance, mean stress, reliability, size, surface finish, and notch sensitivity may control well below yield.
Engineering
Calculate solid-shaft bending stress, torsional shear, von Mises equivalent stress, and a yield-based safety factor against an entered requirement.
SHAFT SAFETY FACTOR
A shaft that carries torque often carries bending at the same section. This calculator keeps the two stress components visible, combines them with the von Mises criterion, and reports both the raw yield ratio and utilization against the entered design-factor requirement.
ENGINEERING DECISION VIEW
Use a low factor or high utilization to revisit section geometry, loading, material basis, and stress raisers. Even a passing nominal-yield screen still needs fatigue, keyway, shoulder, surface, reliability, and deflection evaluation.

| Check | Action / stress 1 | Diameter / stress 2 | Result (MPa or factor) | Equation / decision |
|---|
LIVE CALCULATION PROCESS
sigma_b = 32M/(pi*d^3); tau = 16T/(pi*d^3); sigma_vm = sqrt(sigma_b^2 + 3*tau^2); n = Sy/sigma_vm
The equations use nominal stresses for a solid circular shaft. Bending moment and torque are converted from N*m to N*mm so stress resolves to N/mm2, numerically equal to MPa. The required-factor utilization equals sigma_vm times the entered factor divided by yield strength.
HOW TO USE
SUBJECT FUNDAMENTALS
CALCULATION METHOD
The equations use nominal stresses for a solid circular shaft. Bending moment and torque are converted from N*m to N*mm so stress resolves to N/mm2, numerically equal to MPa. The required-factor utilization equals sigma_vm times the entered factor divided by yield strength.
DEFAULT CASE AUDIT TRAIL
| Symbol | Meaning | Unit |
|---|---|---|
| d | Net solid-shaft diameter | mm |
| M | Bending moment at the checked section | N*m |
| T | Torque at the same section | N*m |
| sigma_b | Nominal bending stress | MPa |
| tau | Nominal torsional shear | MPa |
| Sy | Entered yield strength | MPa |
Independent check:The allowable equivalent stress at n = 1.50 is 355 / 1.50 = 236.67 MPa; the default equivalent stress is lower, and multiplying utilization by the raw factor recovers the required-factor comparison.
DEEPER ANALYSIS
A surface point on a rotating shaft cycles between tension and compression. Endurance, mean stress, reliability, size, surface finish, and notch sensitivity may control well below yield.
A keyway or shoulder needs the correct local diameter and stress-concentration treatment. Reducing yield strength by an arbitrary percentage is not a substitute.
A shaft may remain below yield yet misalign bearings, change gear contact, or exceed runout and vibration limits.
WORKED DECISION CASES
Reaction analysis gives bending and torque at a shoulder. The nominal factor is acceptable, but the fillet and rotating-bending fatigue check is then identified as governing work.
A recorded torque event raises von Mises stress close to yield. The exported calculation preserves the event load and section so inspection and residual-life decisions use the same evidence.
EVIDENCE AND DATA LINEAGE
Keep the shaft drawing and revision, local diameter, shoulders and keyways, material specification and heat treatment, yield basis, bearing and gear reactions, bending-moment and torque diagrams, load-case identifier, units, required-factor source, unrounded stresses, and the separate fatigue and deflection review.
LIMITS AND EXCLUSIONS
RELIABLE SOURCES
FREQUENTLY ASKED QUESTIONS
No. Use the net section and the appropriate fatigue and stress-concentration treatment for the actual keyway geometry.
It is a common ductile-yield criterion for combined normal and shear stress; another criterion may govern specific materials or standards.
Yes. The formula then reduces to the remaining stress component, but both cannot be zero if a finite safety factor is to be interpreted.
It only clears the entered nominal-yield comparison. Fatigue, dynamics, deflection, connections, material condition, and code requirements remain.
Use the load case required by the decision: peak for overload/yield, and a full load spectrum for fatigue.
No. Hollow shafts need the correct outer and inner diameter section properties.
RELATED CALCULATORS
Solve the remaining torque capacity after bending and design reductions.
Test how stiffness and mass changes move the critical-speed separation.
IMPORTANT NOTE
Shaft failure can cause high-energy equipment hazards. Final design and continued-service decisions require verified loads, geometry, material, manufacturing details, fatigue and dynamic analysis, guarding, inspection, and review by the responsible engineer.