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Engineering

Cable Loss Calculator

Calculate temperature-adjusted conductor resistance, circuit I²R loss, voltage drop, annual loss energy, linear heat release, and annual loss cost.

CONDUCTOR LOSS ACCOUNTING

Turn conductor temperature and route resistance into an auditable loss record

This calculator estimates steady resistive cable loss from current, one-way route length, conductor resistance at 20°C, an entered temperature coefficient, conductor operating temperature, phase count, and parallel paths. It then annualizes the instantaneous loss and assigns a user-entered energy price. The result is useful for screening conductor alternatives, not for predicting cable temperature or complete AC loss.

Operating cable loss (kW)
Annual loss energy (kWh)
Annual loss cost
Resistance at temperature (ohm/km)
Resistive voltage drop (V)
Heat release (W/m)

CONDUCTOR LOSS ACCOUNTING

Temperature-corrected cable loss ledger

Use the loss, heat-per-length, and energy consequences to compare conductor or route alternatives. Do not infer conductor temperature from the result; temperature is an input that must come from a thermal calculation, measurement, or credible design case.

Editorial cutaway of a long cable route with heat escaping at measured intervals and an energy meter collecting accumulated annual loss.
The model starts with conductor temperature because resistance—and therefore loss—depends on the operating thermal state.
Temperature-corrected cable loss ledgerLive, unrounded calculation path
Current calculation detail using the entered assumptions
Loss stepMaterial conditionCircuit pathOperating durationCalculated outcome

CURRENT CALCULATION PROCESS

Formula, substitution, intermediate values, and reconciliation

RT = R20[1 + α(T − 20)]; Rpath = RTL/(1000nruns); Ploss = nconductorsI²Rpath; Eloss = Ploss × hours

Resistance is corrected from 20°C to the entered conductor temperature, scaled to route length, and reduced by equal parallel paths. I²R is applied to each loaded conductor; annual energy and cost are calculated only after instantaneous loss is reconciled.

    Intermediate values remain unrounded until display formatting.

    HOW TO USE THIS MODEL

    Estimate loss without mixing temperature or path bases

    1. Select conductor resistance at 20°C for the actual material and cross-section, noting whether it is DC or AC.
    2. Enter conductor operating temperature from a documented thermal case or measurement.
    3. Use line current, one-way route length, phase arrangement, and matched parallel-run count on consistent bases.
    4. Review resistance, I²R loss, voltage drop, and heat per meter before applying hours and energy price.
    5. For variable operation, repeat by load interval and sum energy rather than multiplying peak loss by all annual hours.

    CONDUCTOR LOSS ACCOUNTING FUNDAMENTALS

    Physical quantities behind conductor loss

    Reference resistance
    Conductor resistance specified at a known temperature, commonly 20°C.
    Temperature correction
    Adjustment reflecting the material-dependent rise in resistance with temperature.
    Circuit path resistance
    Resistance of one phase path after length and parallel routes are considered.
    Joule heating
    Electrical energy converted to heat according to I²R.
    Linear heat release
    Modeled watts of conductor loss per route meter, not an allowable thermal rating.
    Annualized loss
    Instantaneous kW multiplied by representative time; validity depends on the load profile.

    MODEL AND FORMULA

    Correct resistance before applying current-squared heating

    RT = R20[1 + α(T − 20)]; Rpath = RTL/(1000nruns); Ploss = nconductorsI²Rpath; Eloss = Ploss × hours

    Resistance is corrected from 20°C to the entered conductor temperature, scaled to route length, and reduced by equal parallel paths. I²R is applied to each loaded conductor; annual energy and cost are calculated only after instantaneous loss is reconciled.

    SYMBOLS AND DEFAULT CASE

    Variable definitions, units, and starting assumptions

    Symbol or inputMeaningUnit or default
    R_TConductor resistance at entered temperatureohm/km
    R_20Reference conductor resistance at 20 Cohm/km
    alphaResistance temperature coefficientper degree C
    R_pathEquivalent one-way path resistance after parallelsohm
    P_lossInstantaneous conductor losskW
    E_lossLoss energy over entered operating hourskWh
    phasesCircuit phases (1 or 3)3
    currentALine current (A)240
    lengthMOne-way route length (m)210
    resistanceOhmPerKmAt20CResistance at 20°C (ohm/km)0.125
    conductorTemperatureCConductor temperature (°C)70
    temperatureCoefficientPercentPerCResistance coefficient (%/°C)0.393
    parallelRunsParallel runs2
    operatingHoursAnnual operating hours5000
    energyPricePerKwhEnergy price per kWh0.12

    Percent inputs are converted to decimal factors once. The live calculation process above substitutes the current values in order, names intermediate quantities, reports the final result, and closes with a reverse or conservation check.

    DEEP ENGINEERING ANALYSIS

    Loss mechanisms beyond the basic conductor model

    AC and harmonic effects

    Skin, proximity, sheath, screen, neutral, and harmonic currents can increase effective loss beyond DC conductor resistance.

    Connection resistance

    Terminations and joints can create localized heating not represented by uniform ohms per kilometre.

    Economic boundary

    Energy price, demand charges, maintenance, outage risk, and conductor capital cost belong in a life-cycle comparison, not the I²R formula.

    WORKED DECISION CASES

    Two loss studies with different time bases

    Continuous process line

    A warm, highly loaded feeder operates near one duty for most of the year, making direct annualization reasonable after resistance temperature is verified.

    Intermittent crane supply

    Peak current is brief and frequent; the analyst sums loss across operating states rather than treating the peak as an 8,760-hour load.

    TECHNICAL GLOSSARY

    Cable loss terms

    Reference temperature
    Temperature at which the base resistance is specified.
    Conductor temperature
    Metal temperature governing resistance, distinct from surrounding ambient.
    Joule loss
    Heat produced by current flowing through resistance.
    Effective path resistance
    Resistance seen by one loaded phase after length and parallels.
    Load factor
    Relationship between actual time-varying demand and a reference maximum.
    Marginal energy price
    Cost assigned to an incremental kWh for the study.

    EVIDENCE AND DATA LINEAGE

    Retain temperature, resistance, and duty-cycle records

    Keep conductor data sheet and resistance basis, material coefficient, measured or calculated conductor temperature, current RMS and harmonic record, phase and neutral loading, route survey, parallel-run equality, operating-hour or interval profile, energy tariff basis, units, and unrounded intermediate results.

    LIMITS AND EXCLUSIONS

    What the basic I²R loss excludes

    • It omits dielectric, sheath, screen, circulating, skin, proximity, harmonic, neutral, joint, and termination losses unless embedded in the entered resistance/current.
    • It assumes a fixed conductor temperature and does not solve thermal equilibrium or cyclic ampacity.
    • The cost output excludes demand charges, escalation, discounting, capital cost, maintenance, and outage economics.

    RELIABLE SOURCES

    References for this method and its boundaries

    FREQUENTLY ASKED QUESTIONS

    Cable loss questions

    Why correct resistance for temperature?

    Metal resistance changes with temperature, so 20°C data can understate energized loss.

    Why use one-way length?

    The formula separately counts loaded conductors; using loop length as well would double-count the path in this model.

    Does heat per meter predict cable temperature?

    No. Temperature depends on heat transfer through insulation, surrounding media, spacing, and ambient conditions.

    Can the energy price be zero?

    Yes for a pure technical loss calculation; annual cost will then be zero while energy loss remains.

    What if current changes every hour?

    Calculate each interval’s I²R energy and sum it; loss at average current is generally not equal to average loss.

    Does this include reactive current?

    Enter actual RMS current, which includes the heating effect of both real and reactive current components.

    IMPORTANT ENGINEERING NOTE

    Loss reduction must preserve electrical and thermal compliance

    Do not choose a conductor or operating current from energy savings alone. A qualified electrical professional must verify ampacity, voltage, protection, fault withstand, installation, thermal environment, power quality, terminations, governing code, and manufacturer requirements.