Load variability
A mean current cannot reproduce mean I² loss. Interval currents or a representative load-duration distribution are better for variable duty.
Engineering
Compare baseline and scenario cable loss while separating current-squared effects from route-length and temperature-adjusted resistance effects.
LOSS DRIVER SENSITIVITY
This calculator is for engineers comparing how a feeder loss estimate responds to changes in load current, route length, and conductor temperature. It preserves one baseline, adjusts resistance with an entered temperature coefficient, and reports the combined I²R consequence alongside isolated current and path-resistance effects. It is a scenario model, not a substitute for a cable thermal solver or time-series load study.
LOSS DRIVER SENSITIVITY
Use the driver separation to identify which evidence deserves refinement. If current dominates, collect interval current and harmonics; if path resistance dominates, verify route, conductor temperature, joints, and AC resistance.

| Sensitivity layer | Baseline | Entered change | Scenario state | Loss consequence |
|---|
CURRENT CALCULATION PROCESS
Ploss = nI²R; Is = Ib(1 + ΔI); Rs = Rb(1 + ΔL)[1 + αΔT]; ΔPloss = (Is²Rs / Ib²Rb − 1) × 100%
The method keeps the I² dependence explicit. Current, route length, and temperature-adjusted material resistance are changed independently and then recombined, so a current increase is not mistakenly treated as a linear loss increase.
Intermediate values remain unrounded until display formatting.
HOW TO USE THIS MODEL
LOSS DRIVER SENSITIVITY FUNDAMENTALS
MODEL AND FORMULA
The method keeps the I² dependence explicit. Current, route length, and temperature-adjusted material resistance are changed independently and then recombined, so a current increase is not mistakenly treated as a linear loss increase.
SYMBOLS AND DEFAULT CASE
| Symbol or input | Meaning | Unit or default |
|---|---|---|
| P_loss | Conductor loss for the stated phase path | kW |
| I_b | Baseline line current | A |
| I_s | Scenario line current | A |
| R_b | Baseline conductor path resistance | ohm |
| R_s | Scenario path resistance | ohm |
| alpha | Resistance temperature coefficient | per degree C |
| baseCurrentA | Baseline current (A) | 220 |
| baseLengthM | Baseline one-way length (m) | 160 |
| baseResistanceOhmPerKm | Baseline resistance (ohm/km) | 0.153 |
| currentChangePercent | Scenario current change (%) | 15 |
| lengthChangePercent | Scenario length change (%) | 8 |
| temperatureChangeC | Conductor temperature change (°C) | 20 |
| temperatureCoefficientPercentPerC | Resistance coefficient (%/°C) | 0.393 |
| phases | Circuit phases (1 or 3) | 3 |
Percent inputs are converted to decimal factors once. The live calculation process above substitutes the current values in order, names intermediate quantities, reports the final result, and closes with a reverse or conservation check.
DEEP ENGINEERING ANALYSIS
A mean current cannot reproduce mean I² loss. Interval currents or a representative load-duration distribution are better for variable duty.
DC resistance, operating-temperature resistance, and effective AC resistance answer different questions; mixing them obscures the real driver.
Temperature affects resistance while loss affects temperature. This one-pass model does not iterate to a thermal equilibrium.
WORKED DECISION CASES
A 15% current increase causes more than a 15% loss increase before the warmer conductor is considered, focusing attention on interval load and ventilation.
A longer route increases path resistance, but a larger conductor reduces base resistance. The alternatives are compared as separate documented scenarios rather than one blended guess.
TECHNICAL GLOSSARY
EVIDENCE AND DATA LINEAGE
Record baseline current timestamp or load case, phase basis, conductor material and size, resistance type and reference temperature, physical route length, operating temperature evidence, coefficients and units, scenario rationale, interval load data when available, and unrounded loss ratios.
LIMITS AND EXCLUSIONS
RELIABLE SOURCES
FREQUENTLY ASKED QUESTIONS
Joule heating is I²R, so current acts twice in the loss ratio.
Yes, provided scenario current remains positive.
Length and temperature alter resistance and then multiply the current-squared ratio; simple addition omits interaction.
It means conductor temperature change. Ambient may influence conductor temperature but is not identical to it.
No. That requires a thermal model with heat transfer and installation conditions.
Only for a stable duty. Variable current requires time-weighted I² integration.
IMPORTANT ENGINEERING NOTE
Use the result to prioritize measurements and alternatives. Final engineering requires verified AC resistance, load profile, cable thermal conditions, protection and fault checks, voltage-drop assessment, manufacturer data, and the governing electrical code.