Static hold
Zero velocity with a static-hold label means the required friction is within capacity, not that mu_s x N is fully mobilized.
Physics calculator
Model a one-dimensional friction trajectory with a static-friction start gate, kinetic-friction motion, exact zero-speed events, and live position and velocity history.
Piecewise motion under dry friction
Follow an object along a signed axis on an incline. The model first decides whether static friction can hold, then applies kinetic friction during each sliding segment and rechecks the static gate whenever velocity reaches zero.
Designed for: For students, lab teams, and preliminary design checks that need the full time history rather than a single stopping-distance number.
LIVE MODEL OUTPUT
Time-ordered state produced from the current inputs and every zero-speed event.
| Time (s) | Friction state | Position (m) | Velocity (m/s) | Acceleration (m/s^2) |
|---|
CURRENT CALCULATION PROCESS
The axis is fixed to the plane. Motion is integrated in constant-acceleration pieces. If a piece would cross zero velocity, the exact crossing time is solved first; the remaining time is then evaluated under the static-friction rule before any reverse motion begins.
| Symbol | Meaning | Unit | Default |
|---|---|---|---|
| m | Translating mass | kg | 12 |
| v0 | Initial signed velocity | m/s | 8 |
| mu_s | Static friction coefficient | unitless | 0.42 |
| mu_k | Kinetic friction coefficient | unitless | 0.30 |
| theta | Incline angle, positive upslope | deg | 0 |
| F | Signed applied force along plane | N | 0 |
| T | Modeled duration | s | 5 |
| dt | Output sample interval | s | 0.25 |
Conversions and rounding: Angles are converted from degrees to radians for sin and cos. All other defaults are already SI. Display values are rounded, but event times and integration retain full floating-point precision.
HOW TO USE
SUBJECT FUNDAMENTALS
RESULT INTERPRETATION
Zero velocity with a static-hold label means the required friction is within capacity, not that mu_s x N is fully mobilized.
Upslope or downslope describes velocity direction. Acceleration may point the other way while the object slows.
The first stop is a diagnostic event. Later motion can occur if the static gate fails after that event.
DEEPER ANALYSIS
If the non-friction drive is inside the static limit when speed reaches zero, the object stays there. If it exceeds the limit, a new kinetic segment starts in the drive direction.
The table is sampled at dt, but stop time is not rounded to that grid. This prevents a coarse reporting interval from moving the physical stop point.
This page assumes the applied force is parallel to the plane. A rope angled away from the surface would reduce N and both friction limits; use a force-component model instead.
WORKED CASES
For m = 12 kg, v0 = 8 m/s, mu_k = 0.30, and no applied force, acceleration is about -2.942 m/s^2. The tote stops near 2.72 s and 10.88 m, then static friction holds because the horizontal drive is zero.
With v0 = 0, the model first compares m x g x sin(theta) with mu_s x m x g x cos(theta). If tan(theta) exceeds mu_s, the cart starts downslope; entering a small nonzero velocity is not required to trigger motion.
ASSUMPTIONS
TECHNICAL LANGUAGE
EVIDENCE AND DATA LINEAGE
Record the contact materials and condition, how mu_s and mu_k were obtained, incline measurement, force direction, mass, time horizon, sample interval, and the exported table. A coefficient copied from a generic table is an assumption, not a test result for the actual interface.
LIMITS AND EXCLUSIONS
RELIABLE SOURCES
FREQUENTLY ASKED QUESTIONS
The solver locates the exact zero of v within a constant-acceleration segment. The sample interval controls reporting density, not event accuracy.
Kinetic friction no longer applies once sliding velocity is zero. The object can remain stopped only if static friction can balance the drive.
Yes. A negative angle makes gravity act toward the positive axis under the stated sign convention.
The simplified launch-and-slide rule assumes a larger or equal breakaway capacity. If your measured interface violates that relation, it needs a more specific friction model.
No. Check end position and the trajectory table; the object may have traveled and then stopped.
Not on this page. Applied force is constant. Split the motion into separately documented intervals or use a time-varying dynamics solver.
IMPORTANT NOTE
This calculator implements an idealized Coulomb-friction model for education and preliminary analysis. Verify coefficients and forces experimentally before relying on the result for safety, braking, lifting, transport, or equipment design.